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The Parking Lot


Alignments to Content Standards: F-IF.A.1

Task

A parking lot charges \$0.50 for each half hour or fraction thereof, up to a daily maximum of \$10.00. Let C(t) be the cost in dollars of parking for t minutes.

  1. Complete the table below.

    t (minutes) C(t) (dollars)
    0
    15
    20
    35
    75
    125
  2. Sketch a graph of C for 0 \leq t \leq 480.
  3. Is C a function of t? Explain your reasoning.
  4. Is t a function of C? Explain your reasoning.

IM Commentary

The purpose of this task is to investigate the meaning of the definition of function in a real-world context where the question of whether there is more than one output for a given input arises naturally. In more advanced courses this task could be used to investigate the question of whether a function has an inverse.

Solution

  1. t (minutes) C(t) (dollars)
    0 0
    15 0.50
    20 0.50
    35 1.00
    75 1.50
    125 2.50
    As a sample calculation, we note that 125 minutes is two full hours (four half-hours) and part of another half hour. Since the ticketing scheme rounds up to the nearest half-hour, we have to pay for five half-hours, at a total cost of $2.50.
  2. Redone_parking_lot_b8361c7ad2f974944824d6f4cb058dca
  3. Yes, C is a function of t because for a given parking time of t minutes there is exactly one charge.
  4. No, t is not a function of C because there are values of C that have many values of t associated with them. For example if you end up paying \$0.50 then you could have parked for any period of time up to half an hour, that is, when C = 0.50 then t can have any value in the range 0 < t \le 30. So the "input" C = 0.50 yields more than one output, which is not allowed for a function.